A function f is continuous on a point x0, if:
> 0, there exists a
> 0, such that
|x-x0|
implies
|f (x)-f (x0)|
.
Given a concret function (who is continuous), a x0 and a
> 0,
you have to find a
> 0 which verifies the above condition. And you
will be noted according to this
: more it is close to the best possible
value, better will be your note.
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